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mqb2766.bsky.social
did:plc:s2uoixske6t33pc4de2ilxsp
Similar to what I did, though I squared up both equations and noted its where d y^2 / dx = 1 (second equation), which gives k (= 1/(2x^(3/2)) directly from the first equation. Then as you say sub to get x.
2025-08-23T12:26:28.502Z